21 lines
450 B
Python
21 lines
450 B
Python
n = 254
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c = 3
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b = 256
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a = 253
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def calc(qo, qh, qg):
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x = ((2 ** qg + 3) ** 2 + 1) / 2 ** (n - 1 - c) - (2 * (2 ** qo + 1)) / 2 ** b - (2 ** qo * 2 ** qh + 2 ** qo) / 2 ** a
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return x
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best = (512, 512, 512)
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for qo in range(1, 128):
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print(qo)
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for qh in range(1, 128):
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for qg in range(1, 128):
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x = calc(qo, qh, qg)
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if x >= 1 and qo + qh + qg < sum(best):
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best = (qo, qh, qg)
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print(best)
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