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Fix unique id for each binary file

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This commit is contained in:
J-Jamet
2021-03-02 14:43:48 +01:00
parent d95a3e00aa
commit 744823cce4
1 changed files with 6 additions and 2 deletions
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8
app/src/main/java/com/kunzisoft/keepass/database/element/database/BinaryPool.kt
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@@ -21,12 +21,16 @@ package com.kunzisoft.keepass.database.element.database
import java.io.File
import java.io.IOException
import kotlin.math.abs
abstract class BinaryPool<T> {
protected val pool = LinkedHashMap<T, BinaryFile>()
private var binaryFileIncrement = 0L // Unique file id (don't use current time because CPU too fast)
// To build unique file id
private var creationId: String = System.currentTimeMillis().toString()
private var poolId: String = abs(javaClass.simpleName.hashCode()).toString()
private var binaryFileIncrement = 0L
/**
* To get a binary by the pool key (ref attribute in entry)
@@ -42,7 +46,7 @@ abstract class BinaryPool<T> {
key: T? = null,
compression: Boolean = false,
protection: Boolean = false): KeyBinary<T> {
val fileInCache = File(cacheDirectory, binaryFileIncrement.toString())
val fileInCache = File(cacheDirectory, "$poolId$creationId$binaryFileIncrement")
binaryFileIncrement++
val newBinaryFile = BinaryFile(fileInCache, compression, protection)
val newKey = put(key, newBinaryFile)